AA <truth_aerator@yahoo.ca> a écrit dans le message de news: aJg29.83696$f05.4145508@news1.calgary.shaw.ca...

> Please all knowledgebale guys help me out here. > > I have an astronomy program that gives me required data on dates that I > need. Here lets see what will be May 15,2003. Will the Earth get so much > gravity from planetx that it will cause our shift, or will we even feel it? > Since she was kind enough to gives the mass and the distance of passage, > everything is set. > > Please go over these results to make sure I entered all numbers correct > (and so that you know that I am correct). > > First of all, what am I doing in this calculation? I am calculating > gravitational forces working ON EARTH on May 15,2003 (the date of the > passing). > > Gravity formula I use is f= m1m2/r^2 , where M1 is earth and M2 is mass > of other objects and R is distance between them. > > My distance is in astronomical units, it is used for all calculations here. > Mass is used as compared to earth. 1 unit of MASS = 1 mass of earth. 2 > means 2x of earth, etc. For example PlanetX being 4x the mass of earth is 4 > units. > PlanetX is 23x the mass of earth: http://zetatalk.com/poleshft/p20.htm > How this calculations is done. I calculate induvidial forces acting on earth > at may 15,2003 of all the planets (including earth moon) and then put in > hypothetical planet X to compare. > > Mearth = 1 > > Msun= 332,950 > > Mmercury 0.55 > > Mvenus = 0.815 > > Mmoon = 0.012 > > Mmars = 0.107 > > Mjupiter=317.9 > > Msaturn=95.15 > > Muranus = 14.54 > > Mneptune = 17.13 > > Mpluto=0.0017 > > Mplanetx = 4 > Mplanetx = 23: http://zetatalk.com/poleshft/p20.htm > earth/sun distance = 1.0108836 AU > > earth/mercury distance = 0.575647 > > earth/venus distance = 1.495540 > > earth/moon distance = 0.0023895594 > > earth/mars = 0.876085 > > earth/jupiter = 5.492346 > > earth/saturn = 9.858417 > > earth/uranus = 20.145459 > > earth/neptune = 29.870548 > > earth/pluto = 29.740010 > > earth/planetx = 0.1506 (all numbers in AU) > > > > Now you take the MASS of the other planet and divide it by distance squared. > > i.e. lets do for sun. > > 332,950 x 1 / 1.010836 AU ^ 2 = 325,849.9 > With the distance given in the above list (1.0108836 AU) it would be: 325,819.2334 > I have done other calculations, like that, on a calculator and piece of > paper. I wrote them down > > and made a sum of them of total solar system force. > > here are the results: > > FOr may 15,2003 > > Sun G affect on earth: 325,849.9 > ??? > Mercury gives = 0.2459 > > Venus = 0.36438 > > Moon = 2101.57 WOW! Other than sun Moon beats all other planets hands > down. Notice 2101.57 force it gives makes us slow down by microseconds in > decades! Cant wait to show you planetx result > > Mars = 0.139409 > > Jupiter = 10.905 > > Saturn = 0.0529 > > Uranus = 0.0358 > > Neptune = 0.01919 > > Pluto = 0.000001922 > > total solar system gravity acting on earth at May 15,2003 = 327,964.2116 > > Planetx. We know it comes 14 million miles from earth. that is 14 > millions miles / AU = 0.1506 > > 4/0.1506^2 = 176.36 ! > 23 / 0.1506^2 = 1014.09 > > > Moon give us 2101.57 Sun gives us 325849.9 and planetX = 176.36 > ... planetX = 1014.09 > Moon is 10x powerful in its affects on earth than PLANET X WILL. When was > the last time moon shifted our poles? > Moon is 2x powerful ... > 176.36 / 328,140.5716 * 100 = 0.1% gravity acting on earth is from > planetX. > 1014.09 / 328,140.5716 * 100 = 0.31% gravity acting on earth is from planetX. > > > Any questions? Please go over calculations, do them yourself and If I am > wrong I'll revise the calculations I made and the result will STILL be in > that neighborhood - insignificant. > The gravific effect would be sufficiently important to induce earthquakes. But the poles shift is to be induced by the magnetic grip instead of a gravity effect. So your work is worthless for the understanding of this mechanism. Amicalement, Beurling.